(5x^3+4)(5x^3-4)=

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Solution for (5x^3+4)(5x^3-4)= equation:


Simplifying
(5x3 + 4)(5x3 + -4) = 0

Reorder the terms:
(4 + 5x3)(5x3 + -4) = 0

Reorder the terms:
(4 + 5x3)(-4 + 5x3) = 0

Multiply (4 + 5x3) * (-4 + 5x3)
(4(-4 + 5x3) + 5x3 * (-4 + 5x3)) = 0
((-4 * 4 + 5x3 * 4) + 5x3 * (-4 + 5x3)) = 0
((-16 + 20x3) + 5x3 * (-4 + 5x3)) = 0
(-16 + 20x3 + (-4 * 5x3 + 5x3 * 5x3)) = 0
(-16 + 20x3 + (-20x3 + 25x6)) = 0

Combine like terms: 20x3 + -20x3 = 0
(-16 + 0 + 25x6) = 0
(-16 + 25x6) = 0

Solving
-16 + 25x6 = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '16' to each side of the equation.
-16 + 16 + 25x6 = 0 + 16

Combine like terms: -16 + 16 = 0
0 + 25x6 = 0 + 16
25x6 = 0 + 16

Combine like terms: 0 + 16 = 16
25x6 = 16

Divide each side by '25'.
x6 = 0.64

Simplifying
x6 = 0.64

Reorder the terms:
-0.64 + x6 = 0.64 + -0.64

Combine like terms: 0.64 + -0.64 = 0.00
-0.64 + x6 = 0.00

Factor a difference between two squares.
(0.8 + x3)(-0.8 + x3) = 0.00

Subproblem 1

Set the factor '(0.8 + x3)' equal to zero and attempt to solve: Simplifying 0.8 + x3 = 0 Solving 0.8 + x3 = 0 Move all terms containing x to the left, all other terms to the right. Add '-0.8' to each side of the equation. 0.8 + -0.8 + x3 = 0 + -0.8 Combine like terms: 0.8 + -0.8 = 0.0 0.0 + x3 = 0 + -0.8 x3 = 0 + -0.8 Combine like terms: 0 + -0.8 = -0.8 x3 = -0.8 Simplifying x3 = -0.8 The solution to this equation could not be determined. This subproblem is being ignored because a solution could not be determined.

Subproblem 2

Set the factor '(-0.8 + x3)' equal to zero and attempt to solve: Simplifying -0.8 + x3 = 0 Solving -0.8 + x3 = 0 Move all terms containing x to the left, all other terms to the right. Add '0.8' to each side of the equation. -0.8 + 0.8 + x3 = 0 + 0.8 Combine like terms: -0.8 + 0.8 = 0.0 0.0 + x3 = 0 + 0.8 x3 = 0 + 0.8 Combine like terms: 0 + 0.8 = 0.8 x3 = 0.8 Simplifying x3 = 0.8 The solution to this equation could not be determined. This subproblem is being ignored because a solution could not be determined. The solution to this equation could not be determined.

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